Diapositive PPT
Au Point Equivalent (R = 1)
Proportions stoéchiométriques
pH = pKaBs + log { [A-]/[AH] }
pH = pKaAc + log { [X-]/[HX] }
2 pH = pKaAc + pKaBs + log { [X-]/[HX] } + log { [A-]/[AH] }
2 pH = pKaAc + pKaBs + log { [X-] [A-] / [HX] [AH] }
{ [X-] [A-] / [HX] [AH] } = 1
pH = 0,5 * [ pKaAc + pKaBs ]